R(x)=3x^2+12x+50

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Solution for R(x)=3x^2+12x+50 equation: 



(R)=3R^2+12R+50

We move all terms to the left:

(R)-(3R^2+12R+50)=0

We get rid of parentheses

-3R^2+R-12R-50=0

We add all the numbers together, and all the variables

-3R^2-11R-50=0

a = -3; b = -11; c = -50;
Δ = b2-4ac
Δ = -112-4·(-3)·(-50)
Δ = -479
Delta is less than zero, so there is no solution for the equation

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